**THE SIX FROGS.— solution**

Move the frogs in the following order: 2, 4, 6, 5, 3, 1 (repeat these moves in the same order twice more), 2, 4, 6. This is a solution in twenty-one moves—the fewest possible.

If *n*, the number of frogs, be even, we require
^{(n˛+n)}/_{2} moves, of which
^{(n˛-n)}/_{2} will be leaps and *n* simple
moves. If *n* be odd, we shall need
(^{(n˛+3n)}/_{2})-4 moves, of which
^{(n˛-n)}/_{2} will be leaps and 2*n*-4
simple moves.

In the even cases write, for the moves, all the even numbers in ascending
order and the odd numbers in descending order. This series must be repeated
˝*n* times and followed by the even numbers in ascending order once only.
Thus the solution for 14 frogs will be (2, 4, 6, 8, 10, 12, 14, 13, 11, 9, 7, 5,
3, 1) repeated 7 times and followed by 2, 4, 6, 8, 10, 12, 14 = 105
moves.

In the odd cases, write the even numbers in ascending order and the odd
numbers in descending order, repeat this series ˝(*n*-1) times, follow with
the even numbers in ascending order (omitting *n*-1), the odd numbers in
descending order (omitting 1), and conclude with all the numbers (odd and even)
in their natural order (omitting 1 and *n*). Thus for 11 frogs: (2, 4, 6,
8, 10, 11, 9, 7, 5, 3, 1) repeated 5 times, 2, 4, 6, 8, 11, 9, 7, 5, 3, and 2,
3, 4, 5, 6, 7, 8, 9, 10 = 73 moves.

This complete general solution is published here for the first time.

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